survivor

Group Members: Logan T. and Emily F.

Question: How much tension is in the rope? How does the angle at which you hold the rope affect balance?

Procedure: 1. Find weight of average women 2. Find force of gravity 3. Find tension in two ropes 4. Find angle that she is holding the rope at to keep balanced 5. Differ the angle to find the position with the least amount of tension

Equipment: Protractor, Meter sticks and rulers, Masses



Conclusion: In this project, we were tying to calculate the tension in the rope as a survivor contestant tries to keep her balance on a wobbly object. The first thing we did was find the angle at which she was holding to the ropes and that turned out to be 67 degrees on both sides. The second thing we did was estimate the weight of Stefanie because her weight was an unknown factor. She is about 5 feet 4 inches tall and we estimated the weight to be 120 pounds. We multiplied 120 by 9.8 to calculate the mass in Newtons and that came out to be 1176 Newtons. After estimating the weight we were than able to calculate the tension. Since we had the weight of 1176 Newtons we divided it by 2 to find the y factor (see picture). We used the sin equation to help calculate the tension. The equation was Sin(67)= 588/ x where x equals 638.78. The tension was 638.78 Newtons. We then had to compare the original tension to other tensions by varying the degree angle. We chose the angles at 60, 30, 10, and 90 degrees with the tension being 678.96, 1176, 3386.16, and 588 Newtons. We figured that by holding the rope with the most tension would allow the contestant to have the most balance. The most tension occurred when Stefanie, the survivor contestant, was holding the rope at an angle of 10 degrees.